lovebanson lovebanson

21-04-2021
Chemistry

contestada

How many moles of NaCl are present in .05 L of 2.3 M NaCl solution?

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kelly1812 kelly1812

21-04-2021

Answer:

n = 1.15 mol

Explanation:

C = n/ V

n= C×V

n= 2.3× 0.5

n = 1.15 mol

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pazgeorge pazgeorge

21-04-2021

N = 1.15 mol so choose dat one :) have a good day <3

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