Answer:
0.14 M
Explanation:
From the question given above, the following data were obtained:
Volume of stock solution (V₁) = 35 mL
Molarity of stock solution (M₁) = 3 M
Volume of diluted solution (V₂) = 750 mL
Molarity of diluted solution (M₂) =?
The molarity (i.e concentration) of the diluted solution can be obtained as follow:
M₁V₁ = M₂V₂
3 × 35 = M₂ × 750
105 = M₂ × 750
Divide both side by 750
M₂ = 105 / 750
M₂ = 0.14 M
Therefore, the concentration of the diluted solution is 0.14 M
