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  • 24-02-2021
  • Mathematics
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rationalise the denominator by 6 root 7 minus 1

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janmilczek
janmilczek janmilczek
  • 24-02-2021

Answer:

Assuming the numerator was 1.

[tex](6\sqrt{7}+1)/251[/tex]

Step-by-step explanation:

Assuming the numerator was 1.

[tex]1/(6\sqrt{7} -1)\\ (6\sqrt{7}+1)/((6\sqrt{7} - 1)(6\sqrt{7} + 1))\\ (6\sqrt{7}+1)/((6\sqrt{7})^2 + 6\sqrt{7} - 7\sqrt{7} - 1)\\(6\sqrt{7}+1)/((6\sqrt{7})^2 - 1)\\(6\sqrt{7}+1)/((36*7 - 1)\\(6\sqrt{7}+1)/251[/tex]

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