Given: the points (1|2) and (0|3) lie on the line.
Question: equation of the line.
Solution:
General equation of a line: y = kx+d,
whereby:
the point (y|x) lies on the line
When x = 0, y = d
The point (0|3) says that d = 3.
So far, the equation is y = kx +3 ……… (1)
Inserting the point (1|2) into (1):
2 = k(1) + 3 => 2–3=k => -1 = k
Putting k into (1):
y = -1x + 3 => y = -x + 3 => y = 3 - x
Answer:
y = 3 - x
