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  • 23-02-2021
  • Mathematics
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Which of the following functions has a factor of x−7?
f(x)=x3−16x2+53x+63
f(x)=x3−2x2−73x−70
f(x)=x3−16x2+53x+70
f(x)=x3−2x2−73x−77

Respuesta :

Adetunmbiadekunle Adetunmbiadekunle
  • 08-10-2021

According to the question, the function that has a factor of x - 7 is f(x) = x³ - 16x² + 53x+ 70

If x - a is a factor of a function f(x), then f(a) = 0

For x - 7 to be a factor of f(x), f(7) must be equal to zero.

For f(x) = x³ - 16x² + 53x+ 70

f(7) = 7³ - 16(7²) + 53(7) + 70

f(7) = 343 - 16(49) + 53(7) + 70

f(7) = 343 - 784 + 371 + 70

f(7) = 0

Since f(7) = 0 for f(x) = x³ - 16x² + 53x+ 70, x - 7 is a factor of f(x) = x³ - 16x² + 53x+ 70

Learn more here: https://brainly.com/question/19273656

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