Answer:
A
Step-by-step explanation:
Using the Pythagorean identity
sin²x + cos²x = 1
Divide all terms by sin²x
[tex]\frac{sin^2x}{sin^2x}[/tex] + [tex]\frac{cos^2x}{sin^2x}[/tex] = [tex]\frac{1}{sin^2x}[/tex] , that is
1 + cot²x = csc²x
Thus
cot²θ + 1 = csc²θ → A
