Answer:
[tex]4\sqrt{2} =5.66[/tex]
Step-by-step explanation:
The square is in the circle, so the diameter is the diagonal line of the square. This divides the square into two right triangles.
Two sides of the right triangle equal 8. This qualifies it as a special right triangle. This triangle has two sides that = x (in this case 8) and the hypotenuse is [tex]x\sqrt{2}[/tex].
Substitute 8 in for x.
[tex]8\sqrt{2}[/tex] is the diameter, so we divide in half to get the radius = [tex]4\sqrt{2}[/tex]
