lanedavis1558 lanedavis1558
  • 25-01-2021
  • Mathematics
contestada

What is the rate of change of the volume of the cylinder at that instance (in cubic kilometers per second)?

Respuesta :

batolisis
batolisis batolisis
  • 26-01-2021

Answer:

hello your question is incomplete attached below is the complete question

answer : -2400 π

Step-by-step explanation:

dr/dt = -12 km/s

h = 2.5 km

r = 40 km at some instant

hence the rate of change of Volume of cylinder at that instance

= dv / dt = [tex]d(\pi r^h ) / dt[/tex]  

              = [tex]\pi h\frac{d(r^2)}{dt}[/tex]  = [tex]-\pi h *2r *dr/dt[/tex]

hence ; dv / dt = -2400 π

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