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22-01-2021
Mathematics

contestada

Y"+y'+ky=0 if y=e(2t)

Find K and general solution

Respuesta :

22-01-2021

Answer:

Auxillary equation: f(m) = m² + m + k = 0

f(2) = 2² + 2 + k = 0

=> k = -6

General solution:

y(t) = C₁e^(2t) + C₂e^(-6t)

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