Respuesta :
Answer:
F' = 9F
Explanation:
The electric force between charges is given by :
[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]
It means,
[tex]F\propto \dfrac{1}{r^2}[/tex]
If distance decreased by a factor of 3, r' = r/3
Net force will become,
[tex]F'=\dfrac{kq_1q_2}{r'^2}\\\\=\dfrac{kq_1q_2}{(\dfrac{r}{3})^2}\\\\=9\dfrac{kq_1q_2}{r^2}\\\\=9\times F[/tex]
It means new force will become 9 times that of the initial force.
Answer:
it is increased by a factor of 9
Explanation:
just took the test
