Respuesta :

luana
[tex]4(x+3)=9x+16+3x\\\\ 4x+12=9x+16+3x\\\\ 4x+12=12x+16\ \ \ | subtract\ 4x\\\\ 12=8x+16\ \ \ | subtract\ 16\\\\ -4=8x\ \ \ | divide\ by\ 8\\\\ x=-\frac{1}{2}[/tex]
konrad509
[tex]4(x+3) = 9x+16+3x\\ 4x+12=12x+16\\ 8x=-4\\ x=-\frac{4}{8}=-\frac{1}{2}[/tex]

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