Answer:
The torque applied perpendicularly to the radius is 0.392 N.m.
Explanation:
Given;
mass of the axle, m = 105.7 g = 0.1057 kg
radius of the axle, r = 37.8 cm = 0.378 m
The torque applied perpendicularly to the radius is given by;
τ = F x r
τ = mg x r
τ = (0.1057 x 9.8) x 0.378
τ = 0.392 N.m
Therefore, the torque applied perpendicularly to the radius is 0.392 N.m.
