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  • 22-10-2020
  • Physics
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Determine the horizontal component of 40m at 330 degrees?

Respuesta :

elcharly64
elcharly64 elcharly64
  • 22-10-2020

Answer:

[tex]a_x=34.64\ m.[/tex]

Explanation:

Rectangular components of a vector

Given a vector [tex]\vec a[/tex], the x-component and y-component of the vector are given respectively by:

[tex]a_x=|\vec a|.\cos\theta[/tex]

[tex]a_y=|\vec a|.\sin\theta[/tex]

Where [tex]\theta[/tex] is the angle measured with respect to the positive horizontal direction.

Let's calculate the horizontal component of a vector with magnitude 40 m and angle 330°

[tex]a_x=40\ m.\cos330^\circ[/tex]

[tex]\boxed{a_x=34.64\ m.}[/tex]

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