hailee67 hailee67
  • 25-09-2020
  • Mathematics
contestada

please don’t skip over me!

show all work

please dont skip over me show all work class=

Respuesta :

surjithayer10 surjithayer10
  • 25-09-2020

Answer:

a,c,d

Step-by-step explanation:

[tex]a. \\4i^9+4i^7\\=4i(i^2)^4+4i(i^2)^3\\=4i(-1)^4+4i(-1)^3\\=4i-4i\\=0\\b.\\2i^{18}-3i^{11}\\=2(i^2)^9-3i(i^2)^5\\=2(-1)^9-3i(-1)^5\\=-2+3i\\c.\\7i^{36}-11i^{11}-11i^9\\=7(i^2)^{18}-11i(i^2)^5-11i(i^2)^4\\=7(-1)^{18}-11i(-1)^5-11i(-1)^4\\=7+11i-11i\\=7\\d.\\8i^{22}-1\\=8(i^2)^{11}-1\\=8(-1)^{11}-1\\=-8-1\\=-9[/tex]

e.

[tex]2i^{27}+4\\=2i(i^2)^{13}+4\\=2i(-1)^{13}+4\\=-2i+4[/tex]

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