Answer:
1.59%.
Explanation:
The following data were obtained from the question:
Measured density = 1.92 g/mL
Accepted density = 1.89 g/mL
Percentage error =...?
The percentage error error of the student can be obtained as follow:
Percentage error = |Measured density – Accepted density |/Accepted density × 100
Percentage error = |1.92 – 1.89|/1.89 × 100
Percentage error = 0.03/1.89 × 100
Percentage error = 1.59%
Therefore, the student percentage error is 1.59%
