shamarriemurphy
shamarriemurphy shamarriemurphy
  • 22-08-2020
  • Mathematics
contestada

Please help me out!!!

Please help me out class=

Respuesta :

Аноним Аноним
  • 22-08-2020

Answer:

[tex]= 2^2^8 \times 3^-^2^0\times 9^4[/tex]

Step-by-step explanation:

[tex]\mathrm{Apply\:exponent\:rule}:\quad \left(a\times\:b\right)^n=a^nb^n\\\left(2^7\times\:3^{-5}\times\:9\right)^4=\left(2^7\right)^4\times\left(3^{-5}\right)^4\times\:9^4\\=\left(2^7\right)^4\cdot \left(3^{-5}\right)^4\cdot \:9^4\\\\= 2^2^8 \times 3^-^2^0\times 9^4[/tex]

Answer Link
Аноним Аноним
  • 22-08-2020

Answer:

[tex] {2}^{28}. {3}^{ - 20}. {9}^{4} [/tex]

Multiply the exponent 4 by each of the exponents inside the parentheses.

Hope this helps..

Good Luck!

Answer Link

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