hkus hkus
  • 23-06-2020
  • Mathematics
contestada

solve 5(x+4)<75 sdsdsd

Respuesta :

ileri ileri
  • 23-06-2020

Answer:

5(x+4) greater than75

=5x+20 greater than 75

5x

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Аноним Аноним
  • 23-06-2020

Answer:

x < 11

Step-by-step explanation:

[tex]5(x+4)<75 \\ open \: the \: bracket \: using \: 5 \\ 5x + 20 < 75 \\ subtract \: - 20 \: from \: both \: sides \: [/tex]

[tex]5x + 20 - 20 < 75 - 20 \\ 5x < 55 \\ divide \: both \: sides \: of \: the \: equation \: \\ by \: 5[/tex]

[tex] \frac{5x}{5} < \frac{55}{5} \\ x < 11[/tex]

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