Answer:
0.442 M
Explanation:
The equation of the reaction must first be written down before the problem can be correctly solved.
2NaOH(aq) + H2SO4(aq) ------> Na2SO4(aq) + 2H2O(l)
Given that;
Concentration of acid CA= 0.65 M
Concentration of base CB= ????
Volume of acid CA= 0.0425L
Volume of base CB= 0.125L
Number of moles of acid = 1
Number of moles of base = 2
From;
CAVA/CBVB= NA/NB
CAVANB= CBVBNA
CB= CAVANB/VBNA
Substituting values;
CB= 0.65 × 0.0425 × 2 / 0.125 × 1
CB= 0.442 M
