Answer:
[tex](x - 3)^{2} + (y + 2)^{2} = 121[/tex]
Step-by-step explanation:
The equation of a circle has the following format:
[tex](x - x_{0})^{2} + (y - y_{0})^{2} = r^{2}[/tex]
In which r is the radius and the centre is the point [tex](x_{0}, y_{0})[/tex]
In this question:
Center at (3,-2), so [tex]x_{0} = 3, y_{0} = -2[/tex]
Radius 11, so [tex]r = 11[/tex]
Then
[tex](x - 3)^{2} + (y - (-2))^{2} = 11^{2}[/tex]
[tex](x - 3)^{2} + (y + 2)^{2} = 121[/tex]
