jaypatel17 jaypatel17
  • 25-08-2016
  • Mathematics
contestada

divide (3+2i)/(-4+5i). express answer in standard form

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dalendrk
dalendrk dalendrk
  • 28-08-2016
[tex]\dfrac{3+2i}{-4+5i}=\dfrac{(3+2i)(-4-5i)}{(-4+5i)(-4-5i)}=\dfrac{-12-15i-8i-10i^2}{(-4)^2-(5i)^2}\\\\=\dfrac{-12-23i+10}{16+25}=\dfrac{-2-23i}{41}=-\dfrac{2}{41}-\dfrac{23}{41}i[/tex]
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