Respuesta :

caylus
Hello,

This method is correct!
[tex] \dfrac{4}{5} *x+ \dfrac{7}{2} = \dfrac{3}{10} \\ ==\textgreater\ \dfrac{5}{4}*( \dfrac{4}{5} *x+ \dfrac{7}{2}) = \dfrac{5}{4}* \dfrac{3}{10} \\ ==\textgreater\ \dfrac{5}{4}* \dfrac{4}{5} *x+ \dfrac{5}{4}*\dfrac{7}{2}=\dfrac{5}{4}* \dfrac{3}{10} \\ ==\textgreater\ x+ \dfrac{35}{8} = \dfrac{3}{8} \\ ==\textgreater\ x+ \dfrac{35}{8}-\dfrac{35}{8} = \dfrac{3}{8} -\dfrac{35}{8}\\ ==\textgreater\ x = -\dfrac{32}{8}\\ Maybe\ this\ line \ is\ missing\\ x=-4 [/tex]

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