selaorr
selaorr selaorr
  • 24-04-2020
  • Mathematics
contestada

911!!! please answer this!!!

911 please answer this class=

Respuesta :

LammettHash
LammettHash LammettHash
  • 24-04-2020

[tex]\left(\dfrac{3a^{-3}b^2}{2a^{-1}b^0}\right)^2[/tex]

First some simplifying:

[tex]\left(\dfrac{3a^1b^2}{2a^3b^0}\right)^2=\left(\dfrac{3b^2}{2a^2}\right)^2=\dfrac{9b^4}{4a^4}[/tex]

Then with [tex]a=-2[/tex] and [tex]b=-3[/tex], we have [tex]a^4=(-2)^4=16=4^2[/tex] and [tex]b^4=(-3)^4=81=9^2[/tex], so

[tex]\dfrac{9b^4}{4a^4}=\dfrac{9\cdot9^2}{4\cdot4^2}=\dfrac{9^3}{4^3}=\dfrac{729}{64}[/tex]

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ckrizek ckrizek
  • 28-10-2020

Answer:

Step-by-step explanation:

Fourth option

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