Answer:
x = 2
Step-by-step explanation:
By the property of intersecting chords outside of the circle.
[tex]EC \times ED = EB \times EA \\ (x + 4)(x + 4 + 1) = (x + 1)(x + 1 + 11) \\ (x + 4)(x + 5) = (x + 1)(x + 12) \\ {x}^{2} + (4 + 5)x + 20 = {x}^{2} + (1 + 12)x + 12 \\ 9x + 20 = 13x + 12 \\ 9x - 13x = 12 - 20 \\ - 4x = - 8 \\ x = \frac{ - 8}{ - 4} \\ \huge \red{ \boxed{x = 2}}[/tex]
