Answer: 90.45 joules
Explanation:
The quantity of Heat Energy (Q) absorbed by ice depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)
Thus, Q = MCΦ
In this case,
Q = ?
Mass of ice = 4.5g
C = 2.010 J/g°C (Though not provided, but the specific heat capacity of ice is 2.010 J/g°C)
Φ = (Final temperature - Initial temperature)
= 10°C - 0°C = 10°C
Then, Q = MCΦ
Q = 4.5g x 2.010 J/g°C x 10°C
Q = 90.45 joules
Thus, 90.45 joules of heat is absorbed by ice.
