kellerpaula kellerpaula
  • 23-03-2020
  • Mathematics
contestada

Trigonometry
Trigonometric Equations
csc x cot x + cot x = 0; x [ 0, 2π ]

Respuesta :

surjithayer10 surjithayer10
  • 23-03-2020

Answer:

x=π/2 ,3π/2

Step-by-step explanation:

cot x(csc x+1)=0

either cot x=0

tanx=∞=tan (π/2)

x=π/2

or csc x=-1

or sin x=-1=-sin (π/2)=sin (π+π/2)=sin (3π/2)

x=3π/2

Answer Link
amna04352
amna04352 amna04352
  • 23-03-2020

Answer:

x = π/2, 3π/2

Step-by-step explanation:

cosecxcotx + cotx = 0

cotx(cosecx + 1) = 0

cotx = 0

x = π/2,

π + π/2 = 3π/2

cosecx = -1

x = 3π/2

x = π/2, 3π/2

Answer Link

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