The height of the baseball going upwards is 35.77 ft
Explanation:
Given:
initial velocity, u = 48 ft/s
Height, h = ?
If the ball is thrown in the air, then the final velocity of the ball will be 0 as the ball later comes to rest.
Acceleration of the ball will be acceleration due to gravity
g = 9.8 m/s²
g = 32.2 ft/s²
We know,
(v)² - (u)² = 2gh
(0)² - (48)² = 2 X 32.2 X h
2304 = 64.4 X h
[tex]h = \frac{2304}{64.4} \\\\h = 35.77 ft[/tex]
Therefore, height of the baseball going upwards is 35.77 ft
