awesomeshreyas2020 awesomeshreyas2020

22-03-2020
Mathematics

contestada

(1901+1902+1903+...+1993)-(101+102+103+...+193)=

Respuesta :

miljanamilovanovic12 miljanamilovanovic12

22-03-2020

Answer:

165600

Step-by-step explanation:

(1901+1902+1903+...+1993) - (101+102+103+...+193)=

(1901-101)+(1902-102)+...+(1993-193)=

1800+1800+...+1800=(We have a series of 92 numbers)

92*1800=165600

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