Answer:
-6, 8
Step-by-step explanation:
Let the numbers be represented by y
Square of y = y^2
Double y = 2 × y = 2y
Square of the number is 48 more than double the number is written mathematically as
y^2 = 2y +48
y^2 - 2y - 48 = 0
This is a quadratic equation and can be solved by method of factorisation
y^2 -2y - 48 = 0
y^2 + 6y - 8y - 48 = 0
(y^2 + 6y) - (8y - 48) = 0
y(y + 6) - 8(y + 6) = 0
(y + 6)(y - 8) = 0
y = -6, 8
The numbers are -6, 8
