rhirhi6489 rhirhi6489
  • 23-11-2019
  • Physics
contestada

What is the free-fall acceleration at the surface of the jupiter?

Respuesta :

miguel9418 miguel9418
  • 23-11-2019

Answer:

24.79 m/s2

Explanation:

Let us assume that there is an object with a mass of 'm' on the

 

Jupiter. Jupiter will attract this object:

[tex]mg_j=G\frac{mM_j}{r_j^{2} }[/tex]

[tex]g_j=G\frac{M_j}{r_j^{2} }[/tex]

[tex]g_j=6.67*10^{-11} \frac{1.9*10^{27} }{71492000^{2} }[/tex]

[tex]g_j=24.79m/s^{2}[/tex]

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