Answer:
ΔT = 1.914 °C
Explanation:
Given data:
Temperature change = ?
Heat absorbed = 800 j
Mass of water = 100 g
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Q = m.c. ΔT
ΔT = Q / m.c
ΔT = 800 j/ 100 g. 4.18 j/g.°C
ΔT = 800 j/ 418 j /.°C
ΔT = 1.914 °C
