isabellamccoy6 isabellamccoy6
  • 25-10-2019
  • Mathematics
contestada

0 = x^2 + 6x - 2 I need to know how to solve for this problem .

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iifeless
iifeless iifeless
  • 25-10-2019

Answer:

x = 2/7

Step-by-step explanation:

0 = x^2 + 6x - 2

0 = x + 6x - 2

0 = 7x - 2

2 = 7x

2/7 = 7x/7

2/7 = x

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wvega313 wvega313
  • 25-10-2019

Answer:

Step-by-step explanation:

This equation should use this type of formula

a(x[ax^{2} +bx+c=0 with this formula

[tex](-b+\sqrt{b^{2}-4(a)(c) }) /2a   \\(b+\sqrt{b^{2}-4(a)(c) }) /2a[/tex]

in this case is imposible because doesn´t exist a negative square root so is indeterminate

Answer Link

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