jmatthews198099 jmatthews198099
  • 24-10-2019
  • Physics
contestada

what is the specific heat of a substance that requires 99,100J of thermal energy to heat 3.47 kg of this substance from 15 C to 41C​

Respuesta :

Moalhazaa
Moalhazaa Moalhazaa
  • 24-10-2019

Answer:

1098.42 J/kg.c°

Explanation:

Q=mcT

you have : Q = 99100

m=3.47kg

and the change in temperature T = 41-15=26c°

Solve for specific heat c :

c = Q/mT === 99100/3.47(26) = 1098.42J/kg . c°

I hope that it's a clear solution and explanation.

Answer Link
johnblack2006 johnblack2006
  • 23-03-2021

Answer: The other guy is way the duck wrong, that’s not one of my answer choices

Explanation: you’re welcome

Answer Link

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