hojessie1 hojessie1
  • 23-10-2019
  • Mathematics
contestada

Find an equation of a line that pass through (4,3) and parallel to y=-4x+1

Respuesta :

Gyzmo
Gyzmo Gyzmo
  • 23-10-2019

Answer:

y = -4x + 19

Step-by-step explanation:

The line parallel to y = -4x + 1 would have the same slope of -4. The coefficient of x will be -4. We can put this into the equation y = -4x + a where a is the y-intercept and a ≠ 1. Now solve for a.

y = -4x + a

plug in 4 for x and 3 for y

3 = -4(4) + a

simplify

3 = -16 + a

+16 both sides

19 = a

a = 19

y = -4x + 19

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