Answer:
5 and 6
Step-by-step explanation:
We have to first solve the given equation [tex]10^{x} =432901[/tex]
Now, taking log in the both sides we get,
[tex]log10^{x} = log 432901[/tex]
⇒ x log 10=log 432901 {Since we have the logarithm property, log aᵇ =b log a}
⇒ x =log 432901 {Since log 10=1}
⇒ x=5.636.
Therefore, the consecutive integers that are under and over the value of x are 5 and 6. (Answer)
