Answer:
[tex]2CH_3COOH+Ba(OH)_2-->(CH_3COO)_2Ba+2H_2O[/tex]
Explanation:
Hello,
Here the requested reaction:
[tex]2CH_3COOH+Ba(OH)_2-->(CH_3COO)_2Ba+2H_2O[/tex]
Whereas the Ba(II) cation is replaced by the outgoing hydride ion into the acid to form barium acetate.
Best regards.
