jazzz8 jazzz8
  • 25-07-2019
  • Mathematics
contestada

What equation is the inverse of y=x^2+16

Respuesta :

Аноним Аноним
  • 25-07-2019

Answer:

[tex]y = \sqrt{x - 16} [/tex]

Step-by-step explanation:

[tex]y = {x}^{2} + 16[/tex]

[tex]x = {y}^{2} + 16[/tex]

[tex]x - 16 = {y}^{2} [/tex]

[tex] \sqrt{x - 16} = y[/tex]

Answer Link
wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 25-07-2019

Answer:

f^-1 (x) = ±sqrt(x-16)

Step-by-step explanation:

To find the inverse of a function, exchange x and y and solve for y

y=x^2+16

Exchange x and y

x = y^2 +16

Then solve for y

Subtract 16 from each side

x-16 = y^2 +16-16

x-16 = y^2

Take the square root of each side

±sqrt(x-16) = sqrt(y^2)

±sqrt(x-16) = y

The inverse

f^-1 (x) = ±sqrt(x-16)

Answer Link

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