Answer:
1+6i
Step-by-step explanation:
Given:
f(x)=x^4 - 2x^3 + 38x^2 - 2 + 37
zero of f(x) = 1-6i
another zero of function = ?
Conjugate Zero theorem:
As per conjugate zero theorem, if a function f(x) has real coefficients and one of zero is a complex number then the conjugate of that complex number will also be a zero of that function i.e. complex zeroes will occur in complex conjugate pairs.
conjugate of 1-6i is 1+6i
hence another zero of f(x) will be 1+6i !
