ddix1966or3894 ddix1966or3894
  • 22-05-2019
  • Mathematics
contestada

The standard form of the equation is x=y^2 + 6y +1. What is the vertex form of the equation? Please show steps.

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kamranT kamranT
  • 23-05-2019

If it is y=x^2 +6x+1 follow this way because if your equation is not for a real function!!!

At first we should find the vertex of parabola: vertex s y = -b/2a ==>-6/2=-3

then find the max or min of the parabola:

Y=-8

so finally we know y=ax^2 + bx + c =(x-h)^2 +k

if vertex is (h,k):

Y=(x+3)^2 -8

Ok?

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