sukhadpul14 sukhadpul14
  • 21-05-2019
  • Mathematics
contestada

please answer this question thanks

please answer this question thanks class=

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PeshwaBajirao42
PeshwaBajirao42 PeshwaBajirao42
  • 21-05-2019

[tex] {x}^{2} - x - \frac{3}{4} = 0 \\ 4{x}^{2} - 4x - 3 = 0 \\ 4 {x}^{2} - (6x - 2x) - 3 = 0 \\ (4 {x}^{2} - 6x) + (2x - 3) = 0 \\ 2x(2x - 3) + 1(2x - 3) = 0 \\ (2x + 1)(2x - 3) = 0 \\ \\ x = \frac{ - 1}{2} \: and \: \frac{3}{2} [/tex]

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