CloudsCantFly CloudsCantFly

24-04-2019
Mathematics

contestada

Solve this system of equations
32=ab^2
128=ab^3

Respuesta :

mkryukova19 mkryukova19

24-04-2019

Answer:

a=2, b=4

Step-by-step explanation:

32=ab²

128=ab³

1) Divide second equation by first one

128/32 = ab³/ab²

4 = b

2) ab²=32

a*4²=32

16a=32

a=2

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