Respuesta :

mattksingh

c

2

−

64

Rewrite  

64

as  

8

2

.

c

2

−

8

2

Since both terms are perfect squares, factor using the difference of squares formula,  

a

2

−

b

2

=

(

a

+

b

)

(

a

−

b

)

where  

a

=

c

and  

b

=

8

.

(

c

+

8

)

(

c

−

8

)

Kamikazeminem

[tex]Answer: \\ {c }^{2} - 64 = (c - 8)(c + 8) \\ \Rightarrow GCF:c + 8[/tex]