mkolodz91 mkolodz91
  • 25-02-2019
  • Mathematics
contestada

LK is tangent to circle J at point K. What is the length of the radius? 6/25 85/12 121/36 157/12

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treegiraffe
treegiraffe treegiraffe
  • 02-08-2019

Answer:

The answer is indeed, 85/12 ; B

Using the Pythagorean theorem, you can use FOIL to solve for the hypotenuse then subtract the radius from the entire hypotenuse to find R. Since all radii are congruent.

[tex]11^2 + r^2 = (6+r)^2\\11^2 + r^2 = (6+r) (6+r)\\121 + r^2 = 36 + 6r + 6r + r^2\\121 + r^2 = 36 + 12r + r^2\\[/tex]

Simplify the rest. We also know that (6+r)^2 is the hypotenuse since angle JKL is a right angle as it is perpendicular to the center and is a tangent.

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