parrishjaclyn0oxmhy1
parrishjaclyn0oxmhy1 parrishjaclyn0oxmhy1
  • 25-02-2019
  • Mathematics
contestada

Enter the given equation in exponential format. log4/5 20x=12y​

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tramserran
tramserran tramserran
  • 26-02-2019

Answer:  [tex]\bold{(20x)^{\frac{1}{12}}=(\frac{4}{5})^y}[/tex]

Step-by-step explanation:

[tex]log_{\frac{4}{5}}(20x)=12y\\\\\text{divide 12 from both sides:}\quad \frac{1}{12}log_{\frac{4}{5}}(20x)=y\\\\\text{condense log (coefficient converts to exponent):}\quad log_{\frac{4}{5}}(20x)^{\frac{1}{12}}=y\\\\\text{use log rules to convert log to exponential form:}\quad (20x)^{\frac{1}{12}}=(\frac{4}{5})^y[/tex]

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