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  • 25-09-2018
  • Mathematics
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tramserran
tramserran tramserran
  • 25-09-2018

  [tex]\frac{r + 5}{r^{2}+5r - 14 }[/tex] ÷ [tex]\frac{r^{2}+4r - 21 }{r - 2}[/tex]

[tex]= \frac{r + 5}{r^{2}+5r - 14 } * \frac{r - 2}{r^{2}+4r - 21 }[/tex]

[tex]=\frac{r + 5}{(r+7)(r - 2)} * \frac{r - 2}{(r + 7)(r - 3)}[/tex]

[tex]=\frac{r + 5}{(r+7)} * \frac{1}{(r + 7)(r - 3)}[/tex]

[tex]=\frac{r + 5}{(r+7)(r + 7)(r - 3)}[/tex]

Answer: B


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