Given the following thermochemical equations:

6C(graphite) + 3H2(g) → C6H6(l) ΔH° = 49.0 kJ

C(graphite) + O2(g) → CO2(g) ΔH° = -393.5 kJ

2H2(g) + O2(g) → 2H2O(l) ΔH° = - 571.6 kJ



Calculate ΔH° for the following reaction:

2C6H6(l) + 15O2(g) → 12CO2(g)+ 6H2O(l) ΔH° = ?