A voltaic cell consists of an Mn/Mn2+ half-cell and a Cd/Cd2+ half-cell. Calculate {Cd2+} when {Mn2+}= 2.12 M and Ecell= 0.706 V. Use reduction potential values of Mn2+ = -1.18 V and for Cd2+ = -0.40 V.
use Ecell=E^0-(RT/nF)lnQ the answer is .007. how do you get this?